Pair Of Lines // April 2026

Verifying Pairs of Straight Lines in Second Degree Equations

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Author Node Archive Editorial
Temporal Read 5 Min Read

Understanding General Second-Degree Equations

A general equation of the second degree in two variables $x$ and $y$ is given by the expression:

$$ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0$$

To determine if such an equation represents a pair of straight lines, we check a specific condition involving its coefficients. This condition is that the determinant of the symmetric matrix formed by these coefficients must be zero. Mathematically, this is expressed as:

$$\Delta = \begin{vmatrix} a & h & g \\ h & b & f \\ g & f & c \end{vmatrix} = abc + 2fgh - af^2 - bg^2 - ch^2 = 0$$

If $\Delta = 0$, the equation represents a pair of straight lines. If $\Delta \neq 0$, it does not.

Step-by-Step Solution

The given equation is:

$$x^2 + 6xy + 9y^2 + 4x + 12y - 5 = 0$$

Step 1: Identify the Coefficients

By comparing the given equation with the standard form $ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0$, we identify the coefficients:

  • $a = 1$
  • $2h = 6 \implies h = 3$
  • $b = 9$
  • $2g = 4 \implies g = 2$
  • $2f = 12 \implies f = 6$
  • $c = -5$

Step 2: Calculate the Determinant $\Delta$

Now, we plug these values into the determinant formula:

$$\Delta = abc + 2fgh - af^2 - bg^2 - ch^2$$

Substitute the values:

  • $abc = (1)(9)(-5) = -45$
  • $2fgh = 2(6)(3)(2) = 72$
  • $-af^2 = -(1)(6)^2 = -36$
  • $-bg^2 = -(9)(2)^2 = -36$
  • $-ch^2 = -(-5)(3)^2 = 5(9) = 45$

Step 3: Compute the Final Sum

$$\Delta = -45 + 72 - 36 - 36 + 45$$

Combine the terms: $$\Delta = (-45 + 45) + 72 - 72$$ $$\Delta = 0 + 0 = 0$$

Conclusion

Since the determinant $\Delta = 0$, the given second-degree equation does represent a pair of straight lines.

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